-6x^2+13x+1=0

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Solution for -6x^2+13x+1=0 equation: 



-6x^2+13x+1=0

a = -6; b = 13; c = +1;
Δ = b2-4ac
Δ = 132-4·(-6)·1
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{193}}{2*-6}=\frac{-13-\sqrt{193}}{-12}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{193}}{2*-6}=\frac{-13+\sqrt{193}}{-12}
$

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